131123221554145 has 4 divisors (see below), whose sum is σ = 157347865864980. Its totient is φ = 104898577243312.

The previous prime is 131123221554107. The next prime is 131123221554163. The reversal of 131123221554145 is 541455122321131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 38713433328144 + 92409788226001 = 6222012^2 + 9613001^2 .

It is a cyclic number.

It is not a de Polignac number, because 131123221554145 - 2²¹ = 131123219456993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131123221554098 and 131123221554107.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13112322155410 + ... + 13112322155419.

It is an arithmetic number, because the mean of its divisors is an integer number (39336966466245).

Almost surely, 2^{131123221554145} is an apocalyptic number.

It is an amenable number.

131123221554145 is a deficient number, since it is larger than the sum of its proper divisors (26224644310835).

131123221554145 is an equidigital number, since it uses as much as digits as its factorization.

131123221554145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26224644310834.

The product of its digits is 144000, while the sum is 40.

Adding to 131123221554145 its reverse (541455122321131), we get a palindrome (672578343875276).

The spelling of 131123221554145 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, two hundred twenty-one million, five hundred fifty-four thousand, one hundred forty-five".