Base | Representation |
---|---|
bin | 11101110100000110000001… |
… | …000010101110001111110011 |
3 | 122012021020221202112020021011 |
4 | 131310012001002232033303 |
5 | 114141310324204213123 |
6 | 1142513102034011351 |
7 | 36422224444324216 |
oct | 3564060102561763 |
9 | 565236852466234 |
10 | 131123221554163 |
11 | 388640562125a3 |
12 | 12858685716b57 |
13 | 5821b362b2547 |
14 | 245457d74777d |
15 | 1025c38a1ee0d |
hex | 7741810ae3f3 |
131123221554163 has 2 divisors, whose sum is σ = 131123221554164. Its totient is φ = 131123221554162.
The previous prime is 131123221554107. The next prime is 131123221554173. The reversal of 131123221554163 is 361455122321131.
It is a strong prime.
It is an emirp because it is prime and its reverse (361455122321131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131123221554163 - 225 = 131123187999731 is a prime.
It is not a weakly prime, because it can be changed into another prime (131123221554103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65561610777081 + 65561610777082.
It is an arithmetic number, because the mean of its divisors is an integer number (65561610777082).
Almost surely, 2131123221554163 is an apocalyptic number.
131123221554163 is a deficient number, since it is larger than the sum of its proper divisors (1).
131123221554163 is an equidigital number, since it uses as much as digits as its factorization.
131123221554163 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 129600, while the sum is 40.
Adding to 131123221554163 its reverse (361455122321131), we get a palindrome (492578343875294).
The spelling of 131123221554163 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, two hundred twenty-one million, five hundred fifty-four thousand, one hundred sixty-three".
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