Base | Representation |
---|---|
bin | 10011000101001011100… |
… | …010101001110001110101 |
3 | 11122100112001002112000112 |
4 | 103011023202221301311 |
5 | 132440400443304001 |
6 | 2442212152552405 |
7 | 163506363335612 |
oct | 23051342516165 |
9 | 4570461075015 |
10 | 1311232400501 |
11 | 4660aa562a11 |
12 | 1921610b2705 |
13 | 9685821187a |
14 | 4766d273509 |
15 | 241950bdcbb |
hex | 1314b8a9c75 |
1311232400501 has 16 divisors (see below), whose sum is σ = 1393581708288. Its totient is φ = 1231700534400.
The previous prime is 1311232400393. The next prime is 1311232400521. The reversal of 1311232400501 is 1050042321131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311232400501 is a prime.
It is a super-2 number, since 2×13112324005012 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311232400521) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2368025 + ... + 2868798.
It is an arithmetic number, because the mean of its divisors is an integer number (87098856768).
Almost surely, 21311232400501 is an apocalyptic number.
It is an amenable number.
1311232400501 is a deficient number, since it is larger than the sum of its proper divisors (82349307787).
1311232400501 is a wasteful number, since it uses less digits than its factorization.
1311232400501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5237092.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 1311232400501 its reverse (1050042321131), we get a palindrome (2361274721632).
The spelling of 1311232400501 in words is "one trillion, three hundred eleven billion, two hundred thirty-two million, four hundred thousand, five hundred one".
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