1311233434031 has 4 divisors (see below), whose sum is σ = 1311250207464. Its totient is φ = 1311216660600.

The previous prime is 1311233434003. The next prime is 1311233434123. The reversal of 1311233434031 is 1304343321131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311233434031 is a prime.

It is a super-2 number, since 2×1311233434031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311233433985 and 1311233434003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311233434631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8268905 + ... + 8425986.

It is an arithmetic number, because the mean of its divisors is an integer number (327812551866).

Almost surely, 2^{1311233434031} is an apocalyptic number.

1311233434031 is a deficient number, since it is larger than the sum of its proper divisors (16773433).

1311233434031 is an equidigital number, since it uses as much as digits as its factorization.

1311233434031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16773432.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1311233434031 its reverse (1304343321131), we get a palindrome (2615576755162).

The spelling of 1311233434031 in words is "one trillion, three hundred eleven billion, two hundred thirty-three million, four hundred thirty-four thousand, thirty-one".