Base | Representation |
---|---|
bin | 1011111011001111100000… |
… | …0101101100110101000111 |
3 | 1201102112101212111122211201 |
4 | 2332303320011230311013 |
5 | 3204313200010300203 |
6 | 43515430550443331 |
7 | 2522224361452630 |
oct | 276637005546507 |
9 | 51375355448751 |
10 | 13112402431303 |
11 | 41a5a3637301a |
12 | 1579331063547 |
13 | 741656b127b6 |
14 | 3349022dc887 |
15 | 17b13c635e1d |
hex | becf816cd47 |
13112402431303 has 8 divisors (see below), whose sum is σ = 14986025799200. Its totient is φ = 11238884818560.
The previous prime is 13112402431283. The next prime is 13112402431357. The reversal of 13112402431303 is 30313420421131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13112402431303 - 213 = 13112402423111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13112402431363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26172918 + ... + 26669203.
It is an arithmetic number, because the mean of its divisors is an integer number (1873253224900).
Almost surely, 213112402431303 is an apocalyptic number.
13112402431303 is a deficient number, since it is larger than the sum of its proper divisors (1873623367897).
13112402431303 is an equidigital number, since it uses as much as digits as its factorization.
13112402431303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52877577.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13112402431303 its reverse (30313420421131), we get a palindrome (43425822852434).
The spelling of 13112402431303 in words is "thirteen trillion, one hundred twelve billion, four hundred two million, four hundred thirty-one thousand, three hundred three".
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