13112403031403 has 64 divisors (see below), whose sum is σ = 15643660032000. Its totient is φ = 10880986659840.

The previous prime is 13112403031391. The next prime is 13112403031423. The reversal of 13112403031403 is 30413030421131.

It is a cyclic number.

It is not a de Polignac number, because 13112403031403 - 2¹² = 13112403027307 is a prime.

It is a super-2 number, since 2×13112403031403² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13112403031423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1987025498 + ... + 1987032096.

It is an arithmetic number, because the mean of its divisors is an integer number (244432188000).

Almost surely, 2^{13112403031403} is an apocalyptic number.

13112403031403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13112403031403 is a deficient number, since it is larger than the sum of its proper divisors (2531257000597).

13112403031403 is a wasteful number, since it uses less digits than its factorization.

13112403031403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12012.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 13112403031403 its reverse (30413030421131), we get a palindrome (43525433452534).

The spelling of 13112403031403 in words is "thirteen trillion, one hundred twelve billion, four hundred three million, thirty-one thousand, four hundred three".