Base | Representation |
---|---|
bin | 11101110100000110110001… |
… | …111100111001010111000001 |
3 | 122012021100001221112210210221 |
4 | 131310012301330321113001 |
5 | 114141314014240013101 |
6 | 1142513315305223041 |
7 | 36422254000044364 |
oct | 3564066174712701 |
9 | 565240057483727 |
10 | 131124042110401 |
11 | 3886443741364a |
12 | 12858874491a81 |
13 | 5821c372b1a92 |
14 | 245461a7040db |
15 | 1025c85aa7aa1 |
hex | 7741b1f395c1 |
131124042110401 has 8 divisors (see below), whose sum is σ = 132924370413344. Its totient is φ = 129323824849440.
The previous prime is 131124042110371. The next prime is 131124042110443. The reversal of 131124042110401 is 104011240421131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131124042110401 - 239 = 130574286296513 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131124042110461) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25381191 + ... + 30107356.
It is an arithmetic number, because the mean of its divisors is an integer number (16615546301668).
Almost surely, 2131124042110401 is an apocalyptic number.
It is an amenable number.
131124042110401 is a deficient number, since it is larger than the sum of its proper divisors (1800328302943).
131124042110401 is an equidigital number, since it uses as much as digits as its factorization.
131124042110401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55520991.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 131124042110401 its reverse (104011240421131), we get a palindrome (235135282531532).
The spelling of 131124042110401 in words is "one hundred thirty-one trillion, one hundred twenty-four billion, forty-two million, one hundred ten thousand, four hundred one".
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