13112441221241 has 4 divisors (see below), whose sum is σ = 13112507404800. Its totient is φ = 13112375037684.

The previous prime is 13112441221177. The next prime is 13112441221267. The reversal of 13112441221241 is 14212214421131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13112441221241 - 2⁶ = 13112441221177 is a prime.

It is a super-2 number, since 2×13112441221241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112441211241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32793701 + ... + 33191138.

It is an arithmetic number, because the mean of its divisors is an integer number (3278126851200).

Almost surely, 2^{13112441221241} is an apocalyptic number.

It is an amenable number.

13112441221241 is a deficient number, since it is larger than the sum of its proper divisors (66183559).

13112441221241 is an equidigital number, since it uses as much as digits as its factorization.

13112441221241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66183558.

The product of its digits is 3072, while the sum is 29.

Adding to 13112441221241 its reverse (14212214421131), we get a palindrome (27324655642372).

The spelling of 13112441221241 in words is "thirteen trillion, one hundred twelve billion, four hundred forty-one million, two hundred twenty-one thousand, two hundred forty-one".