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13112453 = 20996247
BaseRepresentation
bin110010000001…
…010010000101
3220200011220102
4302001102011
511324044303
61145013445
7216311504
oct62012205
926604812
1013112453
117446642
124484285
132941463
141a5483b
151240288
hexc81485

13112453 has 4 divisors (see below), whose sum is σ = 13120800. Its totient is φ = 13104108.

The previous prime is 13112443. The next prime is 13112471. The reversal of 13112453 is 35421131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 35421131 = 291712143.

It is a cyclic number.

It is not a de Polignac number, because 13112453 - 210 = 13111429 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025 + ... + 5222.

It is an arithmetic number, because the mean of its divisors is an integer number (3280200).

Almost surely, 213112453 is an apocalyptic number.

It is an amenable number.

13112453 is a deficient number, since it is larger than the sum of its proper divisors (8347).

13112453 is an equidigital number, since it uses as much as digits as its factorization.

13112453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8346.

The product of its digits is 360, while the sum is 20.

The square root of 13112453 is about 3621.1121219868. The cubic root of 13112453 is about 235.8095094559.

Adding to 13112453 its reverse (35421131), we get a palindrome (48533584).

The spelling of 13112453 in words is "thirteen million, one hundred twelve thousand, four hundred fifty-three".

Divisors: 1 2099 6247 13112453