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1311252115402 = 2655626057701
BaseRepresentation
bin10011000101001100101…
…101110110111111001010
311122100120102012010210001
4103011030231312333022
5132440421020143102
62442214135313214
7163510023036505
oct23051455667712
94570512163701
101311252115402
1146610a6a9019
1219216781b80a
139685c3252a8
1447671b2613c
1524196bb5487
hex1314cb76fca

1311252115402 has 4 divisors (see below), whose sum is σ = 1966878173106. Its totient is φ = 655626057700.

The previous prime is 1311252115361. The next prime is 1311252115421. The reversal of 1311252115402 is 2045112521131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 804323779281 + 506928336121 = 896841^2 + 711989^2 .

It is a super-2 number, since 2×13112521154022 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327813028849 + ... + 327813028852.

Almost surely, 21311252115402 is an apocalyptic number.

1311252115402 is a deficient number, since it is larger than the sum of its proper divisors (655626057704).

1311252115402 is an equidigital number, since it uses as much as digits as its factorization.

1311252115402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655626057703.

The product of its (nonzero) digits is 2400, while the sum is 28.

Adding to 1311252115402 its reverse (2045112521131), we get a palindrome (3356364636533).

The spelling of 1311252115402 in words is "one trillion, three hundred eleven billion, two hundred fifty-two million, one hundred fifteen thousand, four hundred two".

Divisors: 1 2 655626057701 1311252115402