1311260393801 has 4 divisors (see below), whose sum is σ = 1311262928004. Its totient is φ = 1311257859600.

The previous prime is 1311260393771. The next prime is 1311260393819. The reversal of 1311260393801 is 1083930621131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1056537294400 + 254723099401 = 1027880^2 + 504701^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311260393801 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1311260393851) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180170 + ... + 1629411.

It is an arithmetic number, because the mean of its divisors is an integer number (327815732001).

Almost surely, 2^{1311260393801} is an apocalyptic number.

It is an amenable number.

1311260393801 is a deficient number, since it is larger than the sum of its proper divisors (2534203).

1311260393801 is an equidigital number, since it uses as much as digits as its factorization.

1311260393801 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2534202.

The product of its (nonzero) digits is 23328, while the sum is 38.

The spelling of 1311260393801 in words is "one trillion, three hundred eleven billion, two hundred sixty million, three hundred ninety-three thousand, eight hundred one".