131130010210301 has 4 divisors (see below), whose sum is σ = 131131167417792. Its totient is φ = 131128853002812.

The previous prime is 131130010210229. The next prime is 131130010210349. The reversal of 131130010210301 is 103012010031131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131130010210301 - 2⁴² = 126731963699197 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131130010210301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131130010210201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 578433755 + ... + 578660408.

It is an arithmetic number, because the mean of its divisors is an integer number (32782791854448).

Almost surely, 2^{131130010210301} is an apocalyptic number.

It is an amenable number.

131130010210301 is a deficient number, since it is larger than the sum of its proper divisors (1157207491).

131130010210301 is a wasteful number, since it uses less digits than its factorization.

131130010210301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1157207490.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131130010210301 its reverse (103012010031131), we get a palindrome (234142020241432).

The spelling of 131130010210301 in words is "one hundred thirty-one trillion, one hundred thirty billion, ten million, two hundred ten thousand, three hundred one".