Base | Representation |
---|---|
bin | 111101000011111110… |
… | …1010010101010111111 |
3 | 110112110200020201100021 |
4 | 1322013331102222333 |
5 | 4122023240312203 |
6 | 140123523113011 |
7 | 12321344461015 |
oct | 1720775225277 |
9 | 415420221307 |
10 | 131130010303 |
11 | 50680521646 |
12 | 214b7212767 |
13 | c49a032096 |
14 | 64bd5ba8b5 |
15 | 36271765bd |
hex | 1e87f52abf |
131130010303 has 16 divisors (see below), whose sum is σ = 133559184160. Its totient is φ = 128719051776.
The previous prime is 131130010259. The next prime is 131130010327. The reversal of 131130010303 is 303010031131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131130010303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131130010393) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20399776 + ... + 20406202.
It is an arithmetic number, because the mean of its divisors is an integer number (8347449010).
Almost surely, 2131130010303 is an apocalyptic number.
131130010303 is a deficient number, since it is larger than the sum of its proper divisors (2429173857).
131130010303 is a wasteful number, since it uses less digits than its factorization.
131130010303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7786.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 131130010303 its reverse (303010031131), we get a palindrome (434140041434).
The spelling of 131130010303 in words is "one hundred thirty-one billion, one hundred thirty million, ten thousand, three hundred three".
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