1311300540041 has 4 divisors (see below), whose sum is σ = 1343283480084. Its totient is φ = 1279317600000.

The previous prime is 1311300539981. The next prime is 1311300540083. The reversal of 1311300540041 is 1400450031131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 91095312400 + 1220205227641 = 301820^2 + 1104629^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311300540041 - 2¹⁸ = 1311300277897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311300539989 and 1311300540016.

It is not an unprimeable number, because it can be changed into a prime (1311309540041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15991469960 + ... + 15991470041.

It is an arithmetic number, because the mean of its divisors is an integer number (335820870021).

Almost surely, 2^{1311300540041} is an apocalyptic number.

It is an amenable number.

1311300540041 is a deficient number, since it is larger than the sum of its proper divisors (31982940043).

1311300540041 is an equidigital number, since it uses as much as digits as its factorization.

1311300540041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31982940042.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 1311300540041 its reverse (1400450031131), we get a palindrome (2711750571172).

The spelling of 1311300540041 in words is "one trillion, three hundred eleven billion, three hundred million, five hundred forty thousand, forty-one".