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13113025231 = 42293100739
BaseRepresentation
bin11000011011001100…
…01110001011001111
31020211212110200221011
430031212032023033
5203323413301411
610005105350051
7642644606155
oct141546161317
936755420834
1013113025231
115619a62a39
12265b638327
13130c926037
148c578b3d5
1551b32ac21
hex30d98e2cf

13113025231 has 4 divisors (see below), whose sum is σ = 13116130200. Its totient is φ = 13109920264.

The previous prime is 13113025217. The next prime is 13113025241. The reversal of 13113025231 is 13252031131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13113025231 - 213 = 13113017039 is a prime.

It is a super-2 number, since 2×131130252312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113025241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1546141 + ... + 1554598.

It is an arithmetic number, because the mean of its divisors is an integer number (3279032550).

Almost surely, 213113025231 is an apocalyptic number.

13113025231 is a deficient number, since it is larger than the sum of its proper divisors (3104969).

13113025231 is an equidigital number, since it uses as much as digits as its factorization.

13113025231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3104968.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 13113025231 its reverse (13252031131), we get a palindrome (26365056362).

The spelling of 13113025231 in words is "thirteen billion, one hundred thirteen million, twenty-five thousand, two hundred thirty-one".

Divisors: 1 4229 3100739 13113025231