Base | Representation |
---|---|
bin | 10011000101001111110… |
… | …001101001011011100101 |
3 | 11122100200222202201000211 |
4 | 103011033301221123211 |
5 | 132441022140040401 |
6 | 2442223211335421 |
7 | 163511215222264 |
oct | 23051761513345 |
9 | 4570628681024 |
10 | 1311303440101 |
11 | 466136674026 |
12 | 192180a51571 |
13 | 96869b55635 |
14 | 476788865db |
15 | 2419b452951 |
hex | 1314fc696e5 |
1311303440101 has 4 divisors (see below), whose sum is σ = 1353603551104. Its totient is φ = 1269003329100.
The previous prime is 1311303440033. The next prime is 1311303440123. The reversal of 1311303440101 is 1010443031131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1311303440101 - 227 = 1311169222373 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311303440141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21150055455 + ... + 21150055516.
It is an arithmetic number, because the mean of its divisors is an integer number (338400887776).
Almost surely, 21311303440101 is an apocalyptic number.
It is an amenable number.
1311303440101 is a deficient number, since it is larger than the sum of its proper divisors (42300111003).
1311303440101 is an equidigital number, since it uses as much as digits as its factorization.
1311303440101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42300111002.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1311303440101 its reverse (1010443031131), we get a palindrome (2321746471232).
The spelling of 1311303440101 in words is "one trillion, three hundred eleven billion, three hundred three million, four hundred forty thousand, one hundred one".
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