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13113101312010 = 232573676340069
BaseRepresentation
bin1011111011010010000110…
…1111101110000000001010
31201102121012120120110221100
42332310201233232000022
53204321112413441020
643520024154122230
72522250606033000
oct276644157560012
951377176513840
1013113101312010
1141a6264918487
1215794a7120376
1374173884c58b
1433496b064a70
1517b17db86a90
hexbed21bee00a

13113101312010 has 192 divisors, whose sum is σ = 40353277536000. Its totient is φ = 2952544307328.

The previous prime is 13113101311967. The next prime is 13113101312023. The reversal of 13113101312010 is 1021310131131.

13113101312010 is a `hidden beast` number, since 1 + 31 + 1 + 310 + 1 + 312 + 0 + 10 = 666.

13113101312010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1101745 + ... + 5238324.

It is an arithmetic number, because the mean of its divisors is an integer number (210173320500).

Almost surely, 213113101312010 is an apocalyptic number.

13113101312010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113101312010, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20176638768000).

13113101312010 is an abundant number, since it is smaller than the sum of its proper divisors (27240176223990).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113101312010 is a wasteful number, since it uses less digits than its factorization.

13113101312010 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6340170 (or 6340153 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13113101312010 its reverse (1021310131131), we get a palindrome (14134411443141).

The spelling of 13113101312010 in words is "thirteen trillion, one hundred thirteen billion, one hundred one million, three hundred twelve thousand, ten".