13113102000311 has 4 divisors (see below), whose sum is σ = 13328070885624. Its totient is φ = 12898133115000.

The previous prime is 13113102000233. The next prime is 13113102000319. The reversal of 13113102000311 is 11300020131131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13113102000311 - 2⁴² = 8715055489207 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13113102000311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113102000319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107484442565 + ... + 107484442686.

It is an arithmetic number, because the mean of its divisors is an integer number (3332017721406).

Almost surely, 2^{13113102000311} is an apocalyptic number.

13113102000311 is a deficient number, since it is larger than the sum of its proper divisors (214968885313).

13113102000311 is an equidigital number, since it uses as much as digits as its factorization.

13113102000311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214968885312.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13113102000311 its reverse (11300020131131), we get a palindrome (24413122131442).

The spelling of 13113102000311 in words is "thirteen trillion, one hundred thirteen billion, one hundred two million, three hundred eleven", and thus it is an aban number.