Base | Representation |
---|---|
bin | 11000011011001101… |
… | …00000111011001111 |
3 | 1020211212121121021121 |
4 | 30031212200323033 |
5 | 203323423231111 |
6 | 10005111141411 |
7 | 642645346111 |
oct | 141546407317 |
9 | 36755547247 |
10 | 13113102031 |
11 | 561a005707 |
12 | 265b674867 |
13 | 130c951c93 |
14 | 8c57ab3b1 |
15 | 51b343871 |
hex | 30d9a0ecf |
13113102031 has 12 divisors (see below), whose sum is σ = 14269884048. Its totient is φ = 12008161152.
The previous prime is 13113102019. The next prime is 13113102061. The reversal of 13113102031 is 13020131131.
It is not a de Polignac number, because 13113102031 - 213 = 13113093839 is a prime.
It is a super-2 number, since 2×131131020312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13113101996 and 13113102014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113102011) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 258451 + ... + 304996.
It is an arithmetic number, because the mean of its divisors is an integer number (1189157004).
Almost surely, 213113102031 is an apocalyptic number.
13113102031 is a deficient number, since it is larger than the sum of its proper divisors (1156782017).
13113102031 is an equidigital number, since it uses as much as digits as its factorization.
13113102031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 563538 (or 563501 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 13113102031 its reverse (13020131131), we get a palindrome (26133233162).
The spelling of 13113102031 in words is "thirteen billion, one hundred thirteen million, one hundred two thousand, thirty-one".
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