Base | Representation |
---|---|
bin | 111101000100000000… |
… | …1001011101000000101 |
3 | 110112110202011112010121 |
4 | 1322020001023220011 |
5 | 4122024020430041 |
6 | 140124001021541 |
7 | 12321356235655 |
oct | 1721001135005 |
9 | 415422145117 |
10 | 131131030021 |
11 | 50681058792 |
12 | 214b76248b1 |
13 | c49a2cb274 |
14 | 64bd7a4365 |
15 | 36272c87d1 |
hex | 1e8804ba05 |
131131030021 has 4 divisors (see below), whose sum is σ = 138032663200. Its totient is φ = 124229396844.
The previous prime is 131131030003. The next prime is 131131030027. The reversal of 131131030021 is 120030131131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131131030021 - 29 = 131131029509 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131131029977 and 131131030004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131131030027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3450816561 + ... + 3450816598.
It is an arithmetic number, because the mean of its divisors is an integer number (34508165800).
Almost surely, 2131131030021 is an apocalyptic number.
It is an amenable number.
131131030021 is a deficient number, since it is larger than the sum of its proper divisors (6901633179).
131131030021 is an equidigital number, since it uses as much as digits as its factorization.
131131030021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6901633178.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131131030021 its reverse (120030131131), we get a palindrome (251161161152).
The spelling of 131131030021 in words is "one hundred thirty-one billion, one hundred thirty-one million, thirty thousand, twenty-one".
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