1311312023131 has 4 divisors (see below), whose sum is σ = 1430522207064. Its totient is φ = 1192101839200.

The previous prime is 1311312023123. The next prime is 1311312023183. The reversal of 1311312023131 is 1313202131131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311312023131 - 2³ = 1311312023123 is a prime.

It is a super-3 number, since 3×1311312023131³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311312023431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59605091950 + ... + 59605091971.

It is an arithmetic number, because the mean of its divisors is an integer number (357630551766).

Almost surely, 2^{1311312023131} is an apocalyptic number.

1311312023131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1311312023131 is a deficient number, since it is larger than the sum of its proper divisors (119210183933).

1311312023131 is a wasteful number, since it uses less digits than its factorization.

1311312023131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119210183932.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1311312023131 its reverse (1313202131131), we get a palindrome (2624514154262).

The spelling of 1311312023131 in words is "one trillion, three hundred eleven billion, three hundred twelve million, twenty-three thousand, one hundred thirty-one".