Base | Representation |
---|---|
bin | 10011000101010000010… |
… | …010011000111010001111 |
3 | 11122100201120220202210202 |
4 | 103011100102120322033 |
5 | 132441031334220213 |
6 | 2442224115324115 |
7 | 163511351200661 |
oct | 23052022307217 |
9 | 4570646822722 |
10 | 1311312023183 |
11 | 4661404a6688 |
12 | 1921838b063b |
13 | 9686b86c296 |
14 | 47679a7c531 |
15 | 2419c09ab58 |
hex | 13150498e8f |
1311312023183 has 2 divisors, whose sum is σ = 1311312023184. Its totient is φ = 1311312023182.
The previous prime is 1311312023123. The next prime is 1311312023249. The reversal of 1311312023183 is 3813202131131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311312023183 - 210 = 1311312022159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311312023113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655656011591 + 655656011592.
It is an arithmetic number, because the mean of its divisors is an integer number (655656011592).
Almost surely, 21311312023183 is an apocalyptic number.
1311312023183 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311312023183 is an equidigital number, since it uses as much as digits as its factorization.
1311312023183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 1311312023183 in words is "one trillion, three hundred eleven billion, three hundred twelve million, twenty-three thousand, one hundred eighty-three".
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