Search a number
-
+
131131213303 = 1217107749559
BaseRepresentation
bin111101000100000000…
…1111000010111110111
3110112110202111211112211
41322020001320113313
54122024042311203
6140124004554251
712321360631216
oct1721001702767
9415422454484
10131131213303
1150681173462
12214b76b2987
13c49a36380c
1464bd81107d
153627312c6d
hex1e880785f7

131131213303 has 4 divisors (see below), whose sum is σ = 131238964080. Its totient is φ = 131023462528.

The previous prime is 131131213253. The next prime is 131131213319. The reversal of 131131213303 is 303312131131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131131213303 - 233 = 122541278711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131131213373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53873563 + ... + 53875996.

It is an arithmetic number, because the mean of its divisors is an integer number (32809741020).

Almost surely, 2131131213303 is an apocalyptic number.

131131213303 is a deficient number, since it is larger than the sum of its proper divisors (107750777).

131131213303 is a wasteful number, since it uses less digits than its factorization.

131131213303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107750776.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 131131213303 its reverse (303312131131), we get a palindrome (434443344434).

The spelling of 131131213303 in words is "one hundred thirty-one billion, one hundred thirty-one million, two hundred thirteen thousand, three hundred three".

Divisors: 1 1217 107749559 131131213303