1311313321301 has 4 divisors (see below), whose sum is σ = 1311315748704. Its totient is φ = 1311310893900.

The previous prime is 1311313321271. The next prime is 1311313321303. The reversal of 1311313321301 is 1031233131131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311313321301 - 2¹⁰ = 1311313320277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311313321303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3566 + ... + 1619456.

It is an arithmetic number, because the mean of its divisors is an integer number (327828937176).

Almost surely, 2^{1311313321301} is an apocalyptic number.

It is an amenable number.

1311313321301 is a deficient number, since it is larger than the sum of its proper divisors (2427403).

1311313321301 is an equidigital number, since it uses as much as digits as its factorization.

1311313321301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2427402.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1311313321301 its reverse (1031233131131), we get a palindrome (2342546452432).

The spelling of 1311313321301 in words is "one trillion, three hundred eleven billion, three hundred thirteen million, three hundred twenty-one thousand, three hundred one".