13113143011 has 4 divisors (see below), whose sum is σ = 13114048392. Its totient is φ = 13112237632.

The previous prime is 13113142963. The next prime is 13113143033. The reversal of 13113143011 is 11034131131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13113143011 - 2¹⁹ = 13112618723 is a prime.

It is a super-4 number, since 4×13113143011⁴ (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13113143011.

It is not an unprimeable number, because it can be changed into a prime (13113143041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 430606 + ... + 460051.

It is an arithmetic number, because the mean of its divisors is an integer number (3278512098).

Almost surely, 2^13113143011 is an apocalyptic number.

13113143011 is a deficient number, since it is larger than the sum of its proper divisors (905381).

13113143011 is an equidigital number, since it uses as much as digits as its factorization.

13113143011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 905380.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13113143011 its reverse (11034131131), we get a palindrome (24147274142).

The spelling of 13113143011 in words is "thirteen billion, one hundred thirteen million, one hundred forty-three thousand, eleven".