Search a number
-
+
131132002033 = 413198341513
BaseRepresentation
bin111101000100000010…
…0111000111011110001
3110112110210222220111001
41322020010320323301
54122024243031113
6140124033522001
712321400424554
oct1721004707361
9415423886431
10131132002033
1150681661aaa
12214b7a13301
13c49a57b816
1464bd97869b
15362741b7dd
hex1e88138ef1

131132002033 has 4 divisors (see below), whose sum is σ = 134330343588. Its totient is φ = 127933660480.

The previous prime is 131132001983. The next prime is 131132002063. The reversal of 131132002033 is 330200231131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 330200231131 = 1671977246893.

It can be written as a sum of positive squares in 2 ways, for example, as 55106623504 + 76025378529 = 234748^2 + 275727^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131132002033 is a prime.

It is a super-2 number, since 2×1311320020332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131132002033.

It is not an unprimeable number, because it can be changed into a prime (131132002063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1599170716 + ... + 1599170797.

It is an arithmetic number, because the mean of its divisors is an integer number (33582585897).

Almost surely, 2131132002033 is an apocalyptic number.

It is an amenable number.

131132002033 is a deficient number, since it is larger than the sum of its proper divisors (3198341555).

131132002033 is an equidigital number, since it uses as much as digits as its factorization.

131132002033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3198341554.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 131132002033 its reverse (330200231131), we get a palindrome (461332233164).

The spelling of 131132002033 in words is "one hundred thirty-one billion, one hundred thirty-two million, two thousand, thirty-three".

Divisors: 1 41 3198341513 131132002033