Base | Representation |
---|---|
bin | 111101000100000010… |
… | …0111000111100001111 |
3 | 110112110210222220112011 |
4 | 1322020010320330033 |
5 | 4122024243031223 |
6 | 140124033522051 |
7 | 12321400424626 |
oct | 1721004707417 |
9 | 415423886464 |
10 | 131132002063 |
11 | 50681662027 |
12 | 214b7a13327 |
13 | c49a57b83a |
14 | 64bd9786bd |
15 | 362741b80d |
hex | 1e88138f0f |
131132002063 has 2 divisors, whose sum is σ = 131132002064. Its totient is φ = 131132002062.
The previous prime is 131132001983. The next prime is 131132002081. The reversal of 131132002063 is 360200231131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131132002063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131132002093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566001031 + 65566001032.
It is an arithmetic number, because the mean of its divisors is an integer number (65566001032).
Almost surely, 2131132002063 is an apocalyptic number.
131132002063 is a deficient number, since it is larger than the sum of its proper divisors (1).
131132002063 is an equidigital number, since it uses as much as digits as its factorization.
131132002063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 131132002063 its reverse (360200231131), we get a palindrome (491332233194).
The spelling of 131132002063 in words is "one hundred thirty-one billion, one hundred thirty-two million, two thousand, sixty-three".
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