1311320111131 has 4 divisors (see below), whose sum is σ = 1311349618872. Its totient is φ = 1311290603392.

The previous prime is 1311320111077. The next prime is 1311320111141. The reversal of 1311320111131 is 1311110231131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311320111131 - 2²⁹ = 1310783240219 is a prime.

It is a super-2 number, since 2×1311320111131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311320111099 and 1311320111108.

It is not an unprimeable number, because it can be changed into a prime (1311320111141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14687110 + ... + 14776123.

It is an arithmetic number, because the mean of its divisors is an integer number (327837404718).

Almost surely, 2^{1311320111131} is an apocalyptic number.

1311320111131 is a deficient number, since it is larger than the sum of its proper divisors (29507741).

1311320111131 is an equidigital number, since it uses as much as digits as its factorization.

1311320111131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29507740.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1311320111131 its reverse (1311110231131), we get a palindrome (2622430342262).

The spelling of 1311320111131 in words is "one trillion, three hundred eleven billion, three hundred twenty million, one hundred eleven thousand, one hundred thirty-one".