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1311320111141 is a prime number
BaseRepresentation
bin10011000101010000110…
…001001111100000100101
311122100202011010200101202
4103011100301033200211
5132441040422024031
62442225004532245
7163511510015015
oct23052061174045
94570664120352
101311320111141
11466145020247
12192186551085
1396870441761
144767ab85c45
152419cb472cb
hex13150c4f825

1311320111141 has 2 divisors, whose sum is σ = 1311320111142. Its totient is φ = 1311320111140.

The previous prime is 1311320111077. The next prime is 1311320111149. The reversal of 1311320111141 is 1411110231131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1052513898241 + 258806212900 = 1025921^2 + 508730^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311320111141 - 26 = 1311320111077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311320111149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655660055570 + 655660055571.

It is an arithmetic number, because the mean of its divisors is an integer number (655660055571).

Almost surely, 21311320111141 is an apocalyptic number.

It is an amenable number.

1311320111141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311320111141 is an equidigital number, since it uses as much as digits as its factorization.

1311320111141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 1311320111141 its reverse (1411110231131), we get a palindrome (2722430342272).

The spelling of 1311320111141 in words is "one trillion, three hundred eleven billion, three hundred twenty million, one hundred eleven thousand, one hundred forty-one".