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131132013 = 343710671
BaseRepresentation
bin1111101000011…
…10101001101101
3100010202012022020
413310032221231
5232032211023
621002340353
73151414035
oct764165155
9303665266
10131132013
1168025471
1237aba6b9
1321223b0c
14135b68c5
15b7a3de3
hex7d0ea6d

131132013 has 4 divisors (see below), whose sum is σ = 174842688. Its totient is φ = 87421340.

The previous prime is 131132011. The next prime is 131132047. The reversal of 131132013 is 310231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131132013 - 21 = 131132011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131131983 and 131132001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131132011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21855333 + ... + 21855338.

It is an arithmetic number, because the mean of its divisors is an integer number (43710672).

Almost surely, 2131132013 is an apocalyptic number.

It is an amenable number.

131132013 is a deficient number, since it is larger than the sum of its proper divisors (43710675).

131132013 is an equidigital number, since it uses as much as digits as its factorization.

131132013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43710674.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 131132013 is about 11451.2887047703. The cubic root of 131132013 is about 508.0458514114.

Adding to 131132013 its reverse (310231131), we get a palindrome (441363144).

The spelling of 131132013 in words is "one hundred thirty-one million, one hundred thirty-two thousand, thirteen".

Divisors: 1 3 43710671 131132013