13113230200331 has 4 divisors (see below), whose sum is σ = 13113350533752. Its totient is φ = 13113109866912.

The previous prime is 13113230200319. The next prime is 13113230200333. The reversal of 13113230200331 is 13300203231131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113230200331 is a prime.

It is a super-2 number, since 2×13113230200331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13113230200297 and 13113230200306.

It is not an unprimeable number, because it can be changed into a prime (13113230200333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60003101 + ... + 60221246.

It is an arithmetic number, because the mean of its divisors is an integer number (3278337633438).

Almost surely, 2^{13113230200331} is an apocalyptic number.

13113230200331 is a deficient number, since it is larger than the sum of its proper divisors (120333421).

13113230200331 is a wasteful number, since it uses less digits than its factorization.

13113230200331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120333420.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13113230200331 its reverse (13300203231131), we get a palindrome (26413433431462).

The spelling of 13113230200331 in words is "thirteen trillion, one hundred thirteen billion, two hundred thirty million, two hundred thousand, three hundred thirty-one".