Base | Representation |
---|---|
bin | 111101000100000011… |
… | …0000100101000101111 |
3 | 110112110211120122211102 |
4 | 1322020012010220233 |
5 | 4122024332441421 |
6 | 140124044313315 |
7 | 12321403155563 |
oct | 1721006045057 |
9 | 415424518742 |
10 | 131132312111 |
11 | 50681853a69 |
12 | 214b7b4283b |
13 | c49a6599b8 |
14 | 64bda196a3 |
15 | 362747d60b |
hex | 1e88184a2f |
131132312111 has 4 divisors (see below), whose sum is σ = 131336251032. Its totient is φ = 130928373192.
The previous prime is 131132312081. The next prime is 131132312117. The reversal of 131132312111 is 111213231131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111213231131 = 173 ⋅642851047.
It is a cyclic number.
It is not a de Polignac number, because 131132312111 - 210 = 131132311087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131132312117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101968496 + ... + 101969781.
It is an arithmetic number, because the mean of its divisors is an integer number (32834062758).
Almost surely, 2131132312111 is an apocalyptic number.
131132312111 is a deficient number, since it is larger than the sum of its proper divisors (203938921).
131132312111 is an equidigital number, since it uses as much as digits as its factorization.
131132312111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203938920.
The product of its digits is 108, while the sum is 20.
Adding to 131132312111 its reverse (111213231131), we get a palindrome (242345543242).
The spelling of 131132312111 in words is "one hundred thirty-one billion, one hundred thirty-two million, three hundred twelve thousand, one hundred eleven".
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