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131132401 = 199965599
BaseRepresentation
bin1111101000011…
…10101111110001
3100010202012211121
413310032233301
5232032214101
621002342241
73151415131
oct764165761
9303665747
10131132401
1168025794
1237aba981
132122404a
14135b6ac1
15b7a40a1
hex7d0ebf1

131132401 has 4 divisors (see below), whose sum is σ = 131200000. Its totient is φ = 131064804.

The previous prime is 131132399. The next prime is 131132411. The reversal of 131132401 is 104231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131132401 - 21 = 131132399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131132411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30801 + ... + 34798.

It is an arithmetic number, because the mean of its divisors is an integer number (32800000).

Almost surely, 2131132401 is an apocalyptic number.

It is an amenable number.

131132401 is a deficient number, since it is larger than the sum of its proper divisors (67599).

131132401 is an equidigital number, since it uses as much as digits as its factorization.

131132401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67598.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 131132401 is about 11451.3056460825. The cubic root of 131132401 is about 508.0463524881.

Adding to 131132401 its reverse (104231131), we get a palindrome (235363532).

The spelling of 131132401 in words is "one hundred thirty-one million, one hundred thirty-two thousand, four hundred one".

Divisors: 1 1999 65599 131132401