13113253 has 4 divisors (see below), whose sum is σ = 13271328. Its totient is φ = 12955180.

The previous prime is 13113241. The next prime is 13113257. The reversal of 13113253 is 35231131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35231131 = 13 ⋅2710087.

It is a cyclic number.

It is not a de Polignac number, because 13113253 - 2⁹ = 13112741 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13113253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78913 + ... + 79078.

It is an arithmetic number, because the mean of its divisors is an integer number (3317832).

Almost surely, 2^13113253 is an apocalyptic number.

It is an amenable number.

13113253 is a deficient number, since it is larger than the sum of its proper divisors (158075).

13113253 is an equidigital number, since it uses as much as digits as its factorization.

13113253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 158074.

The product of its digits is 270, while the sum is 19.

The square root of 13113253 is about 3621.2225836035. Note that the first 3 decimals coincide. The cubic root of 13113253 is about 235.8143049932.

Adding to 13113253 its reverse (35231131), we get a palindrome (48344384).

It can be divided in two parts, 13113 and 253, that added together give a triangular number (13366 = T₁₆₃).

The spelling of 13113253 in words is "thirteen million, one hundred thirteen thousand, two hundred fifty-three".