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131133012000 = 2535329376819
BaseRepresentation
bin111101000100000100…
…0101111100000100000
3110112110212220012220020
41322020020233200200
54122030022341000
6140124111313440
712321412132224
oct1721010574040
9415425805806
10131133012000
1150682191891
12214b821b880
13c49a843433
1464bdb5c784
15362756aba0
hex1e8822f820

131133012000 has 192 divisors, whose sum is σ = 444406435200. Its totient is φ = 33762892800.

The previous prime is 131133011921. The next prime is 131133012041. The reversal of 131133012000 is 210331131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 159591 + ... + 536409.

It is an arithmetic number, because the mean of its divisors is an integer number (2314616850).

Almost surely, 2131133012000 is an apocalyptic number.

131133012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131133012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222203217600).

131133012000 is an abundant number, since it is smaller than the sum of its proper divisors (313273423200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131133012000 is a wasteful number, since it uses less digits than its factorization.

131133012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 376876 (or 376858 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 131133012000 its reverse (210331131), we get a palindrome (131343343131).

The spelling of 131133012000 in words is "one hundred thirty-one billion, one hundred thirty-three million, twelve thousand".