Base | Representation |
---|---|
bin | 111101000100000100… |
… | …0110001100010001111 |
3 | 110112110212220122021202 |
4 | 1322020020301202033 |
5 | 4122030023122203 |
6 | 140124111420115 |
7 | 12321412165355 |
oct | 1721010614217 |
9 | 415425818252 |
10 | 131133020303 |
11 | 5068219804a |
12 | 214b822463b |
13 | c49a84714c |
14 | 64bdb617d5 |
15 | 362756d388 |
hex | 1e8823188f |
131133020303 has 4 divisors (see below), whose sum is σ = 131133959208. Its totient is φ = 131132081400.
The previous prime is 131133020287. The next prime is 131133020311. The reversal of 131133020303 is 303020331131.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 303020331131 = 7 ⋅43288618733.
It is a cyclic number.
It is not a de Polignac number, because 131133020303 - 24 = 131133020287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131133020383) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213401 + ... + 554802.
It is an arithmetic number, because the mean of its divisors is an integer number (32783489802).
Almost surely, 2131133020303 is an apocalyptic number.
131133020303 is a deficient number, since it is larger than the sum of its proper divisors (938905).
131133020303 is an equidigital number, since it uses as much as digits as its factorization.
131133020303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 938904.
The product of its (nonzero) digits is 486, while the sum is 20.
Adding to 131133020303 its reverse (303020331131), we get a palindrome (434153351434).
The spelling of 131133020303 in words is "one hundred thirty-one billion, one hundred thirty-three million, twenty thousand, three hundred three".
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