1311330411301 has 4 divisors (see below), whose sum is σ = 1311367118400. Its totient is φ = 1311293704204.

The previous prime is 1311330411271. The next prime is 1311330411337. The reversal of 1311330411301 is 1031140331131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311330411301 - 2⁵ = 1311330411269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311330411101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18299911 + ... + 18371428.

It is an arithmetic number, because the mean of its divisors is an integer number (327841779600).

Almost surely, 2^{1311330411301} is an apocalyptic number.

It is an amenable number.

1311330411301 is a deficient number, since it is larger than the sum of its proper divisors (36707099).

1311330411301 is an equidigital number, since it uses as much as digits as its factorization.

1311330411301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36707098.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1311330411301 its reverse (1031140331131), we get a palindrome (2342470742432).

The spelling of 1311330411301 in words is "one trillion, three hundred eleven billion, three hundred thirty million, four hundred eleven thousand, three hundred one".