131134003211401 has 4 divisors (see below), whose sum is σ = 131134228144900. Its totient is φ = 131133778277904.

The previous prime is 131134003211377. The next prime is 131134003211479. The reversal of 131134003211401 is 104112300431131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8483937798400 + 122650065413001 = 2912720^2 + 11074749^2 .

It is a cyclic number.

It is not a de Polignac number, because 131134003211401 - 2¹⁷ = 131134003080329 is a prime.

It is a super-2 number, since 2×131134003211401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131134003215401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111589986 + ... + 112759003.

It is an arithmetic number, because the mean of its divisors is an integer number (32783557036225).

Almost surely, 2^{131134003211401} is an apocalyptic number.

It is an amenable number.

131134003211401 is a deficient number, since it is larger than the sum of its proper divisors (224933499).

131134003211401 is an equidigital number, since it uses as much as digits as its factorization.

131134003211401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 224933498.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131134003211401 its reverse (104112300431131), we get a palindrome (235246303642532).

The spelling of 131134003211401 in words is "one hundred thirty-one trillion, one hundred thirty-four billion, three million, two hundred eleven thousand, four hundred one".