Base | Representation |
---|---|
bin | 11000011011001111… |
… | …10001010100110000 |
3 | 1020211220020100000101 |
4 | 30031213301110300 |
5 | 203324014300334 |
6 | 10005122202144 |
7 | 642651220156 |
oct | 141547612460 |
9 | 36756210011 |
10 | 13113431344 |
11 | 561a210072 |
12 | 265b7b3354 |
13 | 130ca38b40 |
14 | 8c58553d6 |
15 | 51b3ab214 |
hex | 30d9f1530 |
13113431344 has 20 divisors (see below), whose sum is σ = 27361679296. Its totient is φ = 6052352832.
The previous prime is 13113431341. The next prime is 13113431371. The reversal of 13113431344 is 44313431131.
It is a super-2 number, since 2×131134313442 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13113431341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31522464 + ... + 31522879.
Almost surely, 213113431344 is an apocalyptic number.
It is an amenable number.
13113431344 is an abundant number, since it is smaller than the sum of its proper divisors (14248247952).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13113431344 is a wasteful number, since it uses less digits than its factorization.
13113431344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63045364 (or 63045358 counting only the distinct ones).
The product of its digits is 5184, while the sum is 28.
Adding to 13113431344 its reverse (44313431131), we get a palindrome (57426862475).
The spelling of 13113431344 in words is "thirteen billion, one hundred thirteen million, four hundred thirty-one thousand, three hundred forty-four".
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