Base | Representation |
---|---|
bin | 10011000101010010001… |
… | …001110100011101001001 |
3 | 11122100210202211101020220 |
4 | 103011102021310131021 |
5 | 132441112343044040 |
6 | 2442231154340253 |
7 | 163512211254561 |
oct | 23052211643511 |
9 | 4570722741226 |
10 | 1311343331145 |
11 | 46615713a831 |
12 | 19219228a689 |
13 | 968751b16c3 |
14 | 4767dcabda1 |
15 | 2419ebd22d0 |
hex | 13152274749 |
1311343331145 has 48 divisors (see below), whose sum is σ = 2135386169280. Its totient is φ = 687183810688.
The previous prime is 1311343331117. The next prime is 1311343331183. The reversal of 1311343331145 is 5411333431131.
It is not a de Polignac number, because 1311343331145 - 225 = 1311309776713 is a prime.
It is a super-2 number, since 2×13113433311452 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 129331486 + ... + 129341624.
It is an arithmetic number, because the mean of its divisors is an integer number (44487211860).
Almost surely, 21311343331145 is an apocalyptic number.
1311343331145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1311343331145 is a deficient number, since it is larger than the sum of its proper divisors (824042838135).
1311343331145 is a wasteful number, since it uses less digits than its factorization.
1311343331145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12742 (or 12683 counting only the distinct ones).
The product of its digits is 19440, while the sum is 33.
Adding to 1311343331145 its reverse (5411333431131), we get a palindrome (6722676762276).
The spelling of 1311343331145 in words is "one trillion, three hundred eleven billion, three hundred forty-three million, three hundred thirty-one thousand, one hundred forty-five".
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