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131134401413 = 587572231809
BaseRepresentation
bin111101000100000111…
…0000010101110000101
3110112110222111210210222
41322020032002232011
54122030401321123
6140124201154125
712321430010051
oct1721016025605
9415428453728
10131134401413
1150682a50764
12214b878b945
13c49ac0b982
1464c0000c61
1536277426c8
hex1e88382b85

131134401413 has 4 divisors (see below), whose sum is σ = 131136691980. Its totient is φ = 131132110848.

The previous prime is 131134401403. The next prime is 131134401451. The reversal of 131134401413 is 314104431131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 121188926884 + 9945474529 = 348122^2 + 99727^2 .

It is a cyclic number.

It is not a de Polignac number, because 131134401413 - 24 = 131134401397 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131134401403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1057148 + ... + 1174661.

It is an arithmetic number, because the mean of its divisors is an integer number (32784172995).

Almost surely, 2131134401413 is an apocalyptic number.

It is an amenable number.

131134401413 is a deficient number, since it is larger than the sum of its proper divisors (2290567).

131134401413 is an equidigital number, since it uses as much as digits as its factorization.

131134401413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2290566.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 131134401413 its reverse (314104431131), we get a palindrome (445238832544).

The spelling of 131134401413 in words is "one hundred thirty-one billion, one hundred thirty-four million, four hundred one thousand, four hundred thirteen".

Divisors: 1 58757 2231809 131134401413