13113521540113 has 4 divisors (see below), whose sum is σ = 13216777615360. Its totient is φ = 13010265464868.

The previous prime is 13113521540089. The next prime is 13113521540129. The reversal of 13113521540113 is 31104512531131.

It is a happy number.

13113521540113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13113521540113 - 2²⁹ = 13112984669201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13113521543113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51628037433 + ... + 51628037686.

It is an arithmetic number, because the mean of its divisors is an integer number (3304194403840).

Almost surely, 2^{13113521540113} is an apocalyptic number.

It is an amenable number.

13113521540113 is a deficient number, since it is larger than the sum of its proper divisors (103256075247).

13113521540113 is a wasteful number, since it uses less digits than its factorization.

13113521540113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103256075246.

The product of its (nonzero) digits is 5400, while the sum is 31.

The spelling of 13113521540113 in words is "thirteen trillion, one hundred thirteen billion, five hundred twenty-one million, five hundred forty thousand, one hundred thirteen".