13114004111 has 4 divisors (see below), whose sum is σ = 14122773672. Its totient is φ = 12105234552.

The previous prime is 13114004081. The next prime is 13114004203. The reversal of 13114004111 is 11140041131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11140041131 = 14387 ⋅774313.

It is a cyclic number.

It is not a de Polignac number, because 13114004111 - 2²² = 13109809807 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13114004111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114004011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504384761 + ... + 504384786.

It is an arithmetic number, because the mean of its divisors is an integer number (3530693418).

Almost surely, 2^13114004111 is an apocalyptic number.

13114004111 is a deficient number, since it is larger than the sum of its proper divisors (1008769561).

13114004111 is a wasteful number, since it uses less digits than its factorization.

13114004111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1008769560.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13114004111 its reverse (11140041131), we get a palindrome (24254045242).

The spelling of 13114004111 in words is "thirteen billion, one hundred fourteen million, four thousand, one hundred eleven".