131140122052141 has 4 divisors (see below), whose sum is σ = 135370448569984. Its totient is φ = 126909795534300.

The previous prime is 131140122052129. The next prime is 131140122052153. The reversal of 131140122052141 is 141250221041131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (131140122052129) and next prime (131140122052153).

It is a cyclic number.

It is not a de Polignac number, because 131140122052141 - 2¹³ = 131140122043949 is a prime.

It is a super-2 number, since 2×131140122052141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131140122052741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2115163258875 + ... + 2115163258936.

It is an arithmetic number, because the mean of its divisors is an integer number (33842612142496).

Almost surely, 2^{131140122052141} is an apocalyptic number.

It is an amenable number.

131140122052141 is a deficient number, since it is larger than the sum of its proper divisors (4230326517843).

131140122052141 is an equidigital number, since it uses as much as digits as its factorization.

131140122052141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4230326517842.

The product of its (nonzero) digits is 1920, while the sum is 28.

Adding to 131140122052141 its reverse (141250221041131), we get a palindrome (272390343093272).

The spelling of 131140122052141 in words is "one hundred thirty-one trillion, one hundred forty billion, one hundred twenty-two million, fifty-two thousand, one hundred forty-one".