Base | Representation |
---|---|
bin | 111101000100010010… |
… | …0010111001010110101 |
3 | 110112111101112001210000 |
4 | 1322020210113022311 |
5 | 4122033401033331 |
6 | 140124530421513 |
7 | 12321530516130 |
oct | 1721044271265 |
9 | 415441461700 |
10 | 131140252341 |
11 | 5068628763a |
12 | 214ba731899 |
13 | c49c1a9b67 |
14 | 64c0ac5217 |
15 | 3627eeb0e6 |
hex | 1e889172b5 |
131140252341 has 20 divisors (see below), whose sum is σ = 223886710432. Its totient is φ = 74937286728.
The previous prime is 131140252283. The next prime is 131140252387. The reversal of 131140252341 is 143252041131.
131140252341 is a `hidden beast` number, since 1 + 31 + 1 + 40 + 252 + 341 = 666.
It is not a de Polignac number, because 131140252341 - 213 = 131140244149 is a prime.
It is a super-2 number, since 2×1311402523412 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131140052341) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 115643395 + ... + 115644528.
Almost surely, 2131140252341 is an apocalyptic number.
It is an amenable number.
131140252341 is a deficient number, since it is larger than the sum of its proper divisors (92746458091).
131140252341 is an equidigital number, since it uses as much as digits as its factorization.
131140252341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231287942 (or 231287933 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 131140252341 its reverse (143252041131), we get a palindrome (274392293472).
The spelling of 131140252341 in words is "one hundred thirty-one billion, one hundred forty million, two hundred fifty-two thousand, three hundred forty-one".
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