131141100013000 has 256 divisors, whose sum is σ = 395784198950400. Its totient is φ = 39465659520000.

The previous prime is 131141100012947. The next prime is 131141100013009. The reversal of 131141100013000 is 310001141131.

It is a super-2 number, since 2×131141100013000² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131141100013009) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27131331 + ... + 31597330.

It is an arithmetic number, because the mean of its divisors is an integer number (1546032027150).

Almost surely, 2^{131141100013000} is an apocalyptic number.

131141100013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131141100013000 is an abundant number, since it is smaller than the sum of its proper divisors (264643098937400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141100013000 is a wasteful number, since it uses less digits than its factorization.

131141100013000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58728729 (or 58728715 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 131141100013000 its reverse (310001141131), we get a palindrome (131451101154131).

The spelling of 131141100013000 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, thirteen thousand".