13114110001301 has 4 divisors (see below), whose sum is σ = 13140181791072. Its totient is φ = 13088038211532.

The previous prime is 13114110001199. The next prime is 13114110001309. The reversal of 13114110001301 is 10310001141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13114110001301 is a prime.

It is a super-2 number, since 2×13114110001301² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13114110001301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114110001309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13035894131 + ... + 13035895136.

It is an arithmetic number, because the mean of its divisors is an integer number (3285045447768).

Almost surely, 2^{13114110001301} is an apocalyptic number.

It is an amenable number.

13114110001301 is a deficient number, since it is larger than the sum of its proper divisors (26071789771).

13114110001301 is an equidigital number, since it uses as much as digits as its factorization.

13114110001301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26071789770.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 13114110001301 its reverse (10310001141131), we get a palindrome (23424111142432).

The spelling of 13114110001301 in words is "thirteen trillion, one hundred fourteen billion, one hundred ten million, one thousand, three hundred one".