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131141100014402 = 265570550007201
BaseRepresentation
bin11101110100010110101010…
…101011101000101101000010
3122012022222002202000010002012
4131310112222223220231002
5114142103433100430102
61142525220055252522
736423426465613052
oct3564265253505502
9565288082003065
10131141100014402
11388706a0131375
121286003507a142
13582372529a0ba
142455397d77562
1510264333bb752
hex7745aaae8b42

131141100014402 has 4 divisors (see below), whose sum is σ = 196711650021606. Its totient is φ = 65570550007200.

The previous prime is 131141100014389. The next prime is 131141100014423. The reversal of 131141100014402 is 204410001141131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 75180362176921 + 55960737837481 = 8670661^2 + 7480691^2 .

It is a super-2 number, since 2×1311411000144022 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785275003599 + ... + 32785275003602.

Almost surely, 2131141100014402 is an apocalyptic number.

131141100014402 is a deficient number, since it is larger than the sum of its proper divisors (65570550007204).

131141100014402 is an equidigital number, since it uses as much as digits as its factorization.

131141100014402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65570550007203.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 131141100014402 its reverse (204410001141131), we get a palindrome (335551101155533).

The spelling of 131141100014402 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, fourteen thousand, four hundred two".

Divisors: 1 2 65570550007201 131141100014402