131141100341401 has 4 divisors (see below), whose sum is σ = 134339663764404. Its totient is φ = 127942536918400.

The previous prime is 131141100341389. The next prime is 131141100341411. The reversal of 131141100341401 is 104143001141131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 41547757520025 + 89593342821376 = 6445755^2 + 9465376^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141100341401 - 2³³ = 131132510406809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131141100341411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1599281711440 + ... + 1599281711521.

It is an arithmetic number, because the mean of its divisors is an integer number (33584915941101).

Almost surely, 2^{131141100341401} is an apocalyptic number.

It is an amenable number.

131141100341401 is a deficient number, since it is larger than the sum of its proper divisors (3198563423003).

131141100341401 is an equidigital number, since it uses as much as digits as its factorization.

131141100341401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3198563423002.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131141100341401 its reverse (104143001141131), we get a palindrome (235284101482532).

The spelling of 131141100341401 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, three hundred forty-one thousand, four hundred one".