Base | Representation |
---|---|
bin | 10011000101010110001… |
… | …011111110001110001101 |
3 | 11122100222111011112101002 |
4 | 103011112023332032031 |
5 | 132441232204114201 |
6 | 2442242013030045 |
7 | 163513662420446 |
oct | 23052613761615 |
9 | 4570874145332 |
10 | 1311411004301 |
11 | 466191361662 |
12 | 1921b0a85325 |
13 | 968862170a8 |
14 | 47688c862cd |
15 | 241a5aed76b |
hex | 131562fe38d |
1311411004301 has 4 divisors (see below), whose sum is σ = 1311463458492. Its totient is φ = 1311358550112.
The previous prime is 1311411004283. The next prime is 1311411004307. The reversal of 1311411004301 is 1034001141131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1271648650276 + 39762354025 = 1127674^2 + 199405^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311411004301 - 226 = 1311343895437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311411004307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26189576 + ... + 26239601.
It is an arithmetic number, because the mean of its divisors is an integer number (327865864623).
Almost surely, 21311411004301 is an apocalyptic number.
It is an amenable number.
1311411004301 is a deficient number, since it is larger than the sum of its proper divisors (52454191).
1311411004301 is an equidigital number, since it uses as much as digits as its factorization.
1311411004301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52454190.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1311411004301 its reverse (1034001141131), we get a palindrome (2345412145432).
The spelling of 1311411004301 in words is "one trillion, three hundred eleven billion, four hundred eleven million, four thousand, three hundred one".
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